Find the resultant of the following forces:
- 10 N along the x-axis
- 6 N along the y-axis and
- 4 N along the negative x-axis. (8.5 N making 45⁰ with x-axis)
Difficulty: Medium
Solution:
$F_{x}$ = Net force along x-axis = 10.4 = 6 N
$F_{y}$ = Force along y-axis = 5 N
The magnitude of the resultant force = F =?
F = $√F_{x}^{2} + F_{y}^{2}$
F = $√(6)^{2} + (6)^{2}$
F = √36 + 36
= √72 = 8.5 N
Now, θ = $tan^{-1}$ =$\frac{F_{y}}{F_{x}}$
θ = $tan^{-1}$ =$\frac{6}{6}$
θ = $tan^{-1}$ (1)
θ = 45⁰ with x-axis
Sponsored Ads