Find the perpendicular components of a force of 50 N making an angle of 30⁰ with an x-axis. (43.3 N, 25 N)
Difficulty: Easy
Solution:
Force F = 50 N
Angle θ = 30⁰
$F_{x}$ = ? and $F_{y}$ = ?
$F_{x}$ = F cos θ
$F_{x}$= $50 \timescos 30$
= $50 N\times 0.866$ (˙.˙ cos 30⁰ = 0.866)
$F_{x}$ = 43.3 N
Similarly, $F_{y}$ = F sin θ
$F_{y}$= $50 \times 0.5$(˙.˙ sin 30⁰ = 0.5)
$F_{y}$= 25 N
Sponsored Ads