A chocolate wrapper is 6.7 cm long and 5.4 cm wide. Calculate its area up to a reasonable number of significant figures.
$(36 cm^{2})$
Difficulty: Easy
Solution:
Length of the chocolate wrapper I = 6.7 cm
Width of chocolate wrapper w = 5.4 cm
Area = A = ?
Area = $Length \times Width$
A = $l \times w$
A=$6.7cm \times5.4$ cm = $36.18 cm^{2} = 36cm^{2}$
Note:
The answer should be in two significant figures because in data the least significant figures are two therefore answer is 36 $cm^{2}$
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