Two masses 52 kg and 48 kg are attached to the ends of a string that passes over a frictionless pulley. Find the tension in the string and acceleration in the bodies when both the masses are moving vertically. $(500 N, 0.4 ms^{-2})$
Difficulty: Easy
Solution:
m1 = 52 kg and m2 = 48 kg
Tension T =?
Acceleration a =?
T =$\frac{ (2m_1 m_2)}{(m_1+ m_2 )}$g
T = $\frac{(2 ×52 ×48)}{(52 + 48)}\times$ 10
T = $\frac{49920}{100}$
T = 499.20 ≈ 500 N
a =$\frac{(m_1 – m_2)}{(m_1+ m_2 )}g$
a = $\frac{(52 - 48)}{(52 + 48)}\times 10$
a =$\frac{4}{100}\times 10$
a = 0.4 $ms^{-2}$
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