Two masses 26 kg and 24 kg are attached to the ends of a string which passes over a frictionless pulley. 26 kg is lying over a smooth horizontal table. 24 N mass is moving vertically downward. Find the tension in the string and the acceleration in the bodies. (125 N, 4.8 $ms^{-2}$)
Difficulty: Medium
Solution:
m1 = 24 kg and m2 = 26 kg
Tension T =?
Acceleration a =?
T =$\frac{(m_1 m_2)}{(m_1+ m_2 )}g$
T = $\frac{(24 ×26)}{(24 + 26)}\times$ 10
T = $\frac{6240}{50}$
T = 124.8 ≈ 125 N
a =$\frac{(m_1)}{(m_1+ m_2 )}$ g
a = $\frac{24}{(24 + 26)}\times10$
a = $\frac{24}{50}\times10$
a = 4.8 $ms^{-2}$
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