Table of Contents
Question:
Find the order of the following matrices.
Difficulty: Easy
Solution:
Order of the Matrix:
The number of rows and columns in a Matrix specifies its order.
Ans. (i) Matrix A has two rows and two columns
So, its order = number of rows x number of columns = 2-by-2.
Ans. (ii) Matrix B has two rows and two columns
So, its order = number of rows x number of columns = 2-by-2.
Ans. (iii) Matrix C has one row and two columns
So, its order = number of rows x number of columns = 1-by-2.
Ans. (iv) Matrix D has three rows and one column
So, its order = number of rows x number of columns = 3-by-1.
Ans. (v) Matrix E has three rows and two columns
So, its order = number of rows x number of columns = 3-by-2.
Ans. (vi) Matrix F has one row and one column
So, its order = number of rows x number of columns = 1-by-1.
Ans. (vii) Matrix G has three rows and three columns
So, its order = number of rows x number of columns = 3-by-3.
Ans. (viii) Matrix A has two rows and three columns
So, its order = number of rows x number of columns = 2-by-3.
Question:
Which of the following matrices are equal?
Difficulty: Easy
Solution:
Solving C
C = $\left[ 5-2 \right]$
C = $\left[ 3 \right]$
Solving G
G = $\left[ \begin{matrix} 3-1 \\ 3+3 \\ \end{matrix} \right]$
G = $\left[ \begin{matrix} 2 \\ 6 \\ \end{matrix} \right]$
Solving I
I = $\left[ \begin{matrix} 3 & 3+2 \\ \end{matrix} \right]$
I = $\left[ \begin{matrix} 3 & 5 \\ \end{matrix} \right]$
Solving J
J = $\left[ \begin{matrix} 2+2 & 2-2 \\ 2+4 & 2+0 \\ \end{matrix} \right]$
J = $\left[ \begin{matrix} 4 & 0 \\ 6 & 2 \\ \end{matrix} \right]$
Now Matrices are said to be equal if
(i) They are of same order
(ii) Their corresponding values are equal
So, according to this definition
(a) Matrices A and C are equal, A = C.
(b) Matrices B and I are equal, B = I.
(c) Matrices E, H and J are equal, E = H = J.
(d) Matrices F and G are equal, F = G.
Question:
Find the values of a, b, c, and d which satisfy the matrix equation.
$\left[ \begin{matrix} a+c & a+2b \\ c-1 & 4d-6 \\ \end{matrix} \right] = \left[ \begin{matrix} 0 & -7 \\ 3 & 2d \\ \end{matrix} \right]$
Difficulty: Easy
Solution:
As, $\left[ \begin{matrix} a+c & a+2b \\ c-1 & 4d-6 \\ \end{matrix} \right]$ = $\left[ \begin{matrix} 0 & -7 \\ 3 & 2d \\ \end{matrix} \right]$
By comparing the corresponding elements, we get
$a + c = 0$
$a = -c$ ---------------(i)
$a + 2b = -7$
$2b = - (a+7)$ ---------------(ii)
$c - 1 = 3$
$c = 3 + 1$
$c = 4$ ---------------(iii)
By putting the value of “c” in equation (i), we will get
$a = -4$ ---------------(iv)
By putting the value of “a” in equation (ii), we will get
$2b = - (-4+7)$
$2b = - (3)$
$b = -{\large \frac{3}{2}} $
$b = - 1.5$ ---------------(v)
Similarly,
$4d - 6 = 2d$
$4d - 2d = 6$
$2d = 6$
$d =-{\large \frac{6}{2}}$
$d = 3$ ---------------(vi)
From equations (iii), (iv), (v) and (vi) we get
$a = - 4$, $b = - 1.5$, $c = 4$ and $d = 3$
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