$\left(\frac{1}{2}x+3\right)-\left(\frac{2}{3}x-5\right)$

Which of the following is equivalent to the expression above?

Question

Accepted Answer

$-\frac{1}{6}x+8$

Answer

$-\frac{1}{6}x-2$

Answer

$-\frac{1}{3}x^{2}+\frac{1}{2}x+15$

Answer

$-\frac{1}{3}x^{2}-\frac{9}{2}x-15$