$6x^{2}+5x-7=0$

What are the solutions to the given equation?

Question

Accepted Answer

$\frac{-5\pm\sqrt{25+168}}{12}$

Answer

$\frac{-6\pm\sqrt{25+168}}{12}$

Answer

$\frac{-5\pm\sqrt{36+168}}{12}$

Answer

$\frac{-6\pm\sqrt{36+168}}{12}$